[Twisted-web] parsing xml coming from a socket
Antonis Kaklis
kaklis at gmail.com
Tue Jun 1 09:46:58 EDT 2010
Hi to all, and since this is my first post, congratulations for the perfect
framework.
i have the following code
class SimpleServer(LineReceiver):
def connectionMade(self):
print 'Connection from: ', self.transport.client
def connectionLost(self, reason):
print self.transport.client, 'Disconnected'
def dataReceived(self, line):
"""Here the XML Parser"""
p = xml.parsers.expat.ParserCreate()
p.StartElementHandler = start_element
p.EndElementHandler = end_element
p.CharacterDataHandler = char_data
p.Parse(line, 1)
I got the following error
--- <exception caught here> ---
File "/usr/lib/python2.6/site-packages/Twisted-10.0.0-py2.6-linux-
x86_64.egg/twisted/internet/selectreactor.py", line 146, in
_doReadOrWrite
why = getattr(selectable, method)()
File "/usr/lib/python2.6/site-packages/Twisted-10.0.0-py2.6-linux-
x86_64.egg/twisted/internet/tcp.py", line 460, in doRead
return self.protocol.dataReceived(data)
File "stdiodemo.py", line 419, in dataReceived
p.Parse(line, 1)
xml.parsers.expat.ExpatError: syntax error: line 1, column 0
The XML Message is coming in the form of:
POST /test/pcp/Listener HTTP/1.1
user-agent:hjahs
Host:127.0.0.1
Content-Length: 547
<pttv_control_message version="1.0-M4-SNAPSHOT" build="599"
xmlns="http://1270.0.01/pttv<http://www.google.com/url?sa=D&q=http://1270.0.01/pttv&usg=AFQjCNEPqmRku5kV0nsb3RICWIxQ8vOV9A>">
<cmdReply>
<code>200</code>
<message>OK, found 5 session entries</message>
<sessionList>
<session>
<id>06d4d59bfdfe10139dd874</id>
<subscriberId>82</subscriberId>
<deviceClass>and</deviceClass>
</session>
</sessionList>
</cmdReply>
</pttv_control_message>
Please give me some hints.
How to parse the incoming XML and how to ommit the headers from the
beginning of the message?
Thanks in advance
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