[Twisted-Python] A problem with runUntilCurrent
Itamar Shtull-Trauring
itamar at itamarst.org
Mon May 17 10:24:15 EDT 2004
On Mon, 2004-05-17 at 10:20, Christopher Armstrong wrote:
> No, callLater(0,) doesn't call the function synchronously, it calls it
> in the next reactor iteration. i.e., not "*right* now", but "ASAP".
That's what it's *supposed* to do. But Glyph's code had a bug for the
following case:
def infinite(): reactor.callLater(0, infinite)
reactor.callLater(0, infinite)
where it would just call infinite() over and over and over and over.
--
Itamar Shtull-Trauring http://itamarst.org
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