[Twisted-Python] A problem with runUntilCurrent

[Christopher Armstrong]

Bill la Forge wrote:

> This means that when you do a callLater with a delay of 0,
> runUntilCurrent will immediately call the delayed function, which then
> calls callLater, and again the delayed function is immediately called, etc.

No, callLater(0,) doesn't call the function synchronously, it calls it 
in the next reactor iteration. i.e., not "*right* now", but "ASAP".

-- 
  Twisted | Christopher Armstrong: International Man of Twistery
   Radix  |          Release Manager,  Twisted Project
---------+           http://radix.twistedmatrix.com/
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