118,122c118,135
<     key = [ord(i) for i in key]
<     buf = list(buf)
<     for i, char in enumerate(buf):
<         buf[i] = chr(ord(char) ^ key[i % 4])
<     return "".join(buf)
---
>     ## Please don't bring back the xor vs encryption masking debate... :0
>     k = unpack('!Q', key * 2)[0]
>     ## Some long data to process, use long xor
>     div, mod = divmod(len(buf), 8)
>     if mod:
>         ## The buffer legth is not a 8 bytes multiple, need to adjust with rest
>         if div:
>             ## More than 8 bytes: unmask all long words except last
>             longs = [pack('!Q', k ^ unpack('!Q', buf[i:i+8])[0]) for i in range(0, div*8, 8)]
>             ## Append the rest (last 0..7 bytes)
>             longs.append(pack('!Q', k ^ unpack('!Q', buf[div*8:] + " "*(8-mod))[0])[:mod])
>             return "".join(longs)
>         else:
>             ## Short: all bytes at once
>             return pack('!Q', k ^ unpack('!Q', buf[div*8:] + " "*(8-mod))[0])[:mod]
>     else:
>         ## The buffer legth is a 8 bytes multiple
>         return "".join(pack('!Q', k ^ unpack('!Q', buf[i:i+8])[0]) for i in xrange(0, div*8, 8))