[Twisted-Python] Returning a Deferred as a result from another Deferred
exarkun at divmod.com
Tue Oct 9 06:12:49 EDT 2007
On Mon, 8 Oct 2007 22:59:49 -0700, Ryan Fugger <rfugger at gmail.com> wrote:
>On 10/8/07, Jean-Paul Calderone <exarkun at divmod.com> wrote:
>> On Fri, 5 Oct 2007 19:00:51 -0700, Ryan Fugger <rfugger at gmail.com> wrote:
>> >On 10/5/07, Jonathan Lange <jml at mumak.net> wrote:
>> >> On 10/6/07, Ryan Fugger <rfugger at gmail.com> wrote:
>> >> > Returning a Deferred as a result from another Deferred seems to be
>> >> > disallowed by an assertion at the start of the callback chain.
>> You've misread the code. Jonathan is correct.
>What is that assertion guarding against then? Seems to me like it is
>explicitly preventing you from doing this:
>d1 = Deferred()
>d2 = Deferred()
>In fact, that exact code raises the AssertionError in question. If
>the intention is to allow this, then the assertion needs to be
Here's what it sounds like "returning a Deferred as a result from another
d = Deferred()
This is a useful and very common thing to do. I see this isn't what you
were attempting to describe now, though.
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