[Twisted-Python] Passing arguments to application

Stephan Popp Stephan.Popp at iisb.fraunhofer.de
Wed Jun 29 08:18:03 EDT 2005

maybe I haven't searched enough, but I don't find anything that halps me to 
solve my problem.
I've got a serverapplication. The problem is in the following lines:

application = service.Application("TwistedServerApp")
internet.TCPServer(8800, pb.ServerFactory...)

I don't want to start this with a predetermined port. More like:

twistd -y TwistedServerApp.tac 8800

Is this somehow possible? sys.argv seems impossible to use.


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