[Twisted-Python] How to get the IP address of a client using XML-RPC

[Jp Calderone]

Daniel Newton wrote:
> 
> I have a simple XML-PRC server similar to the example below:
> 
> from twisted.web import xmlrpc, server
> 
> class Example(xmlrpc.XMLRPC):
>     """An example object to be published."""
> 
>     def xmlrpc_add(self, a, b):
>         """Return sum of arguments."""
>         return a + b

       def xmlrpc_whatIsMyAddress(self):
           return self.transport.getPeer().host

> 
> if __name__ == '__main__':
>     from twisted.internet import reactor
>     r = Example()
>     reactor.listenTCP(7080, server.Site(r))
>     reactor.run()
> 
> I want to be able to get the address of the client that calls the xmlrpc 
> method can anyone help me with this?
> 
> thanks in advance
> 
> Daniel Newton
> 

   Jp