[Twisted-Python] Ldaptor BoF at Linux-Kongress

Tommi Virtanen tv at debian.org
Sun Aug 25 11:54:06 EDT 2002

	Hi. I'm thinking of organizing a BoF at Linux-Kongress,
	about Ldaptor and Scalemail etc. My email/LDAP-related
	Twisted thingies, that is.

	Please give feedback on the email I am about to send.
	What would you like to hear? What would motivate you to
	joining the brainw^H^H^H^H^H^HBoF?

	Latest version of the mail will be at

	Current edition follows.

From: Tommi Virtanen <tv at debian.org>
To: jochen.topf at guug.de
Subject: Linux-Kongress BoF: Scalemail & Ldaptor

	Hi. I'd like to organize a BoF at the Linux-Kongress, 2002.
	Trying to use the ones at
	as a template for the rest of this mail..

Scalemail & Ldaptor: integrating Postfix, Courier-IMAP and LDAP with
Python and Twisted

by Tommi Virtanen <tv at debian.org>


Managing large amounts of user accounts can be tedious. Scalemail is
an attempt at solving the email part of that equation, and Ldaptor
 is a pure-Python LDAP library and a set of utilities and
applications, including a web-based search/edit interface. Together,
this mighty duo aims to allow an admin to manage thousands of user
accounts across multiple domains and servers, delegating
responsibility for account management to non-techical people where

This BoF will introduce the tools used, give an overview of the
architectures of Scalemail and Ldaptor, and solicit feedback from
email system admins and programmers for future enhancements.

Software to integrate:
	- Postfix (http://www.postfix.org/)
	- Courier-IMAP (http://www.inter7.com/courierimap/)
	- OpenLDAP (http://www.openldap.org/)

Tools used:
	- Python (http://www.python.org/)
	- Twisted (http://www.twistedmatrix.com/)

New software created:
	- Scalemail (http://scalemail.sourceforge.net/)
	- Ldaptor (http://ldaptor.bkbits.net/ for now)

Who should attend?
	- Email administrators of sites with over 100 users.
	- Hackers interested in email and/or LDAP.
	- Python programmers who want to see Twisted stuff.

double a,b=4,c;main(){for(;++a<2e6;c-=(b=-b)/a++);printf("%f\n",c);}

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